Answer:
32.5 moles of O2(g) are necessaries for a complete reaction
Step-by-step explanation:
Based on the reaction of combustion of C4H10(g):
C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)
1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.
That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:
5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =
32.5 moles of O2(g) are necessaries for a complete reaction