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What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?

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Answer:

32.5 moles of O2(g) are necessaries for a complete reaction

Step-by-step explanation:

Based on the reaction of combustion of C4H10(g):

C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.

That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:

5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =

32.5 moles of O2(g) are necessaries for a complete reaction

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