Answer:
1.204x10²⁴ molecules of water
Step-by-step explanation:
The ethane dioic acid is the same oxalic acid. The molecular formula of oxalic acid is:
C2H2O4
Usually, the oxalic acid is dihydrated, that means contains 2 moles of water per mole of acid.
Using Avogadro's number, 1 mole of ethane dioic acid contains 6.022x10²³ molecules of ethane dioic acid. As we have 2 molecules of water per molecule of ethane dioic acid, the molecules of water are.
6.022x10²³ molecules ethane dioic acid * (2molecules Water / molecule Ethane Dioic acid) =
1.204x10²⁴ molecules of water