Question

I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, at a temperature of 290 K. Then the Temperature went to 390 K and the volume of 1.1 Liter. What is the New Pressure? Please help I have been asking this for weeks

Answer 1

P₂ = 1.22 kPa

Step-by-step explanation:

This problem can be solved using the equation of state:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

`((1\ kPa)(1\ liter))/(290\ k) =((P_2)(1.1\ liter))/(390\ k)\\\\P_2= ((1\ kPa)(1\ liter)(390\ k))/((290\ k)(1.1\ liter))`

P₂ = 1.22 kPa