Question

A student uses a spring to launch a marble vertically in the air. The mass of the marble is

0.02 kg and when the spring is stretched 0.08 m it exerts a force of 58 N. What is
the maximum height the marble can reach?

Answer 1

the maximum height reached by the marble is 11.84 m.

Step-by-step explanation:

Given;

mass of the marble, m = 0.02 kg

extension of the string, x = 0.08 m

force applied to the string, F = 58 N

Apply the principle of conservation of energy;

elastic potential energy = gravitational potential energy

¹/₂fx = mgh

`h = (Fx)/(2mg) \\\\h = (58 \ * \ 0.08)/(2 \ * \ 0.02 \ * \ 9.8) \\\\h = 11.84 \ m`

Therefore, the maximum height reached by the marble is 11.84 m.