Find the zeros x^3+8x^2-20x+48

asked Dec 4, 2022 69.3k views

1 vote

Find the zeros

x^3+8x^2-20x+48

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4 votes

Answer:

Graph each side of the equation. The solution is the x-value of the point of intersection.

x≈−10.37392996

Explanation:

Andrew Schulman answered Dec 11, 2022

9.2k points

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