=x^(2) -6x+5

Question

asked Nov 23, 2023 182k views

2 Answers

Sagneta · Answer 1 · 2023-11-23T12:16:21+0000

a) y-intercept = 5

b)
(x-1)(x-5)

step 1: find factors of 1st and last terms

step 2: multiply the factors "rainbow" style (like in the picture) and add the products to make sure they equal the middle term

$x^(2) -6x+5\\1,1$
-1,-5

$(-1)+(-5)=-6\\=(x-1)(x-5)$

c)
x=1,5

$(x-1)(x-5)\\x-1=0$
x-5=0

x=1
x=5

d) AoS=
x=3

e)
vertex=(3,-4)

$(h,k)\\h=-(b)/(2a) \\h=-((-6))/(2(1)) \\h=-(-3)\\h=3\\k=f(3)=(3)^2-6(3)+5\\k=9-18+5\\k=-4$