Question

What is the gravitational force between the Earth

(mEarth = 5.98 x 1024 kg, rEarth = 6.378 x 106 m)
and a 15,000 kg satellite in Earth’s orbit 575-km above Earth’s surface?

Answer:
____________ Newtons
I really need help on this! Can someone please help? Thank you!

Answer 1

The gravitational force between the Earth and a satellite can be calculated using Newton's Law of Universal Gravitation.

Step-by-step explanation:

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation:

F = [G * (m1 * m2)] / r^2

where F is the gravitational force, G is the gravitational constant (6.674 × 10-11 N·m² kg-2), m1 and m2 are the masses of the two objects, and r is the distance between the objects. In this case, we have the mass of Earth (5.98 x 1024 kg), the mass of the satellite (15,000 kg), and the distance from the satellite to Earth's surface (575 km + Earth's radius).

Using these values, we can calculate the gravitational force between the Earth and the satellite:

F = [(6.674 × 10-11 * (5.98 x 1024) * (15,000))] / (6.378 x 106)^2

This equation yields the gravitational force in Newtons.

Answer 2

17.7MN

Step-by-step explanation:

Given Data

m1 = 5.98 x 10^24 kg

m2= 15,000 kg

R= 6.378 x 10^6 m+575-km

R= 6.378 x 10^3+575*10^3-km

R= 581378m

G = 6.673 x 10-11 N m^2/kg2

This net centripetal force is the result of the gravitational force that attracts the satellite towards the central body and can be represented as

F =GM1M2 / R^2

F =6.673 x 10-11* 5.98 x 10^24*15,000 / 581378^2

F =6.673 x 10^-11* 5.98 x 10^24*15,000 / 581378^2

F= 39.90454*10^13*15,000/ 581378^2

F= 598.5681*10^16/338000378884

F= 17709095.5335N

F= 17.7MN