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Which quadratic equation defines the function that has zeros at -8 and 6? x^2+2x-48 =0 x^2-2x-48=0 x^2+2x+48=0 x^2−2x+48=0

Which quadratic equation defines the function that has zeros at -8 and 6? x^2+2x-48 =0 x^2-2x-48=0 x^2+2x+48=0 x^2−2x+48=0
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Which quadratic equation defines the function that has zeros at -8 and 6?

x^2+2x-48 =0
x^2-2x-48=0
x^2+2x+48=0
x^2−2x+48=0

User Cibin Joseph
by
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2 Answers

5 votes
X^2+2x-48=0 is the answer
User JYoThI
by
8.1k points
2 votes
It would be the first one because to me that is the only one that makes sense
User Quilby
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8.0k points
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