Question

6.

A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softbal's acceleration is - 16
Ft/s2. This can be modeled with the equation (h=height, t=time) h(t)=16t^2 +50t+ 3
What is the time at which the softball would hit the ground it it were not hit or caught?

A.) .5 seconds
B.)3.12 seconds
c.) 3.18 seconds
D. ) 2.42

Answer 1

Using their equation and the fact that the ball will fall 3 ft before reaching the ground:

3 = 16 t^2 + 50 t + 3 represents the given situation

16 t^2 + 50 t = t (16 t + 50) = 0

16 t + 50 = 0

t = 50 / 16 = 3.12 sec