Question

A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s new volume?

Answer 1

8.68 L is the new volume

Step-by-step explanation:

You use Boyle's law for this.

`P_(1)V_(1)=P_(2)V_(2)`

`P_(1)` = first pressure

`P_(2)` = second pressure

`V_(1)` = first volume

`V_(2)` = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)(
`V_(2)`)

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) =
`V_(2)` = 8.68 L

Hope this helps :)