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On a hot day, a 15.0 kg window increased from 20.0 degrees C to 26.7 degrees C. How much heat energy did the glass window absorb? (specific heat of glass = 0.840 J/gC)

User Theosem
by
8.2k points

1 Answer

2 votes

Answer: The heat energy absorbed by glass window is 84420 J.

Step-by-step explanation:

Given: Mass = 15 kg (1 kg = 1000 g) = 15000 g

Initial temperature =
20^(o)C

Final temperature =
26.7^(o)C

Specific heat capacity =
0.840 J/g^(o)C

Formula used is as follows.


q = m * C * (T_(2) - T_(1))

where,

q = heat energy

m = mass of substance

C = specific heat capacity


T_(1) = initial temperature


T_(2) = final temperature

Substitute the values into above formula as follows.


q = m * C * (T_(2) - T_(1))\\ q = 15000 g * 0.840 J/g^(o)C * (26.7 - 20)^(o)C\\q = 84420 J

Thus, we can conclude that the heat energy absorbed by glass window is 84420 J.

User Kiran Pagar
by
8.8k points
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