a vertical pole cast a shadow of 20m long when the altitude of the sun is 60°what is the height of the pole?

asked Mar 24, 2023 48.8k views

11 votes

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7 votes

$\tt Tg~\alpha =(height~of~the~pole)/(shadow)\\\\height=Tg~60* 20=34.64~m$

Anders Elton answered Mar 26, 2023

3.2k points

5 votes

Answer:

20√3

Explanation:

20 x tan(60°)

20√3

Deadwards answered Mar 29, 2023

3.5k points

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