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2 votes
URGENT!!

The length of a rectangle is five more than double the width. Find the dimensions if the
perimeter is 88m.

User JasperTack
by
3.1k points

2 Answers

5 votes

Answer:

The length is 31m and the width is 13m.

Explanation:

Start by translating the word problem into an equation. 5 more than double the width is written as 2w + 5. Then substitute that into the equation for the perimeter. It should look something like this:

88 = 2(2w +5) + 2w

Then simplify by combining like terms and solve for the width (w).

88 = 6w + 10

78 = 6w

13 = w

Now that we have the width, we can plug it back into the equation we made for the length.

l = 2w + 5

l = 2(13) + 5

l = 26 + 5

l = 31

I hope this could help!

User Dmx
by
3.5k points
5 votes

Answer:

13, 31

Explanation:

Set the width as x.

Length: 2x + 5

Perimeter:

(x) + (2x + 5) + (x) + (2x + 5) = 88

Simplify.

6x + 10 = 88

Solve.

6x = 78

x = 13

Substitute this into the previous equations

Width: 13

Length: 31

User Zswqa
by
3.6k points