Question

Find equation of a line passing through the points
(0, 2) and (6, 20)

Answer 1

`\tt slope=m=(y_2-y_1)/(x_2-x_1)`

`\tt =(20-2)/(6-0)=3`

equation:

y-y₁ = m(x-x₁), for point (0,2)

y-2 = 3(x-0)

y-2 = 3x

y = 3x+2

Answer 2

Explanation:

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