Question

On a hot day, a 15.0 kg window increased from 20.0 degrees C to 26.7 degrees C. How much heat energy did the glass window absorb? (specific heat of glass = 0.840 J/gC)

Answer 1

Answer: The heat energy absorbed by the glass window is 84420 J.

Step-by-step explanation:

Given: Mass = 15.0 kg (1 kg = 1000 g) = 15000 g

Specific heat capacity =
`0.840^(o)C`

Initial temperature =
`20^(o)C`

Final temperature =
`26.7^(o)C`

Formula used to calculate heat energy is as follows.

`q = m * C * (T_(2) - T_(1))`

where,

q = heat energy

m = mass of substance

C = specific heat capacity

`T_(1)` = initial temperature

`T_(2)` = final temperature

Substitute the values into above formula as follows.

`q = m * C * (T_(2) - T_(1))\\= 15000 g * 0.840J/g^(o)C * (26.7 - 20.0)^(o)C\\= 84420 J`

Thus, we can conclude that heat energy absorbed by the glass window is 84420J.