The answer is C
Step-by-step explanation:
Since there are three C’s on the left side, there needs to be three C’s on the right.
The coefficient in front of CO2 is now 3CO2
Next, balance the H’s.
Since there are 8 H’s on the left, there needs to be 8 on the right.
Since H2O already has two H’s you just need to multiply 2 by 4 to get 8 H’s. The coefficient in front of the H2O needs to be 4.
Finally, balance the O’s.
In 3CO2, there are 6 O’s because 3 x 2 = 6.
In 4H2O, there are 4 O’s.
6 + 4 = 10
There are 10 O’s on the right, so there needs to be 10 on the left.
Since O2 already has 2 O’s, you need to multiply it by 5 because 5 x 2 = 10.
The coefficient in front of the O2 is 5.
The coefficient in front of C3H8 is 1 because it is already balanced.
The final balanced equation has the following coefficients:
1, 5, 3, 4