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25 votes
An elephant weighs 40,000 newtons. Each of its four feet has an area of 500cm^2. Of the elephant stands on one foot, what pressure does it put on the ground?

User Treva
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2 Answers

26 votes
26 votes

Pressure :- Force/area

= 40000n/125cm²

=40000n×10/125cm²

=3.2×10 Pascal

User Chrstpsln
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3.3k points
9 votes
9 votes

Answer:


\large\boxed{\sf Pressure = 3.2* 10^6\ Pa }

Step-by-step explanation:

Here it is given that a elephant weighs 40,000 N and the area of its 4 feet is 500cm² . We need to find out what pressure will it exert if it stands on one foot .

Since area of 4 feet was 500cm² ,

Then the area of 1 foot will be 500cm²/4 = 125cm² .

Now , as we know that ;


\sf\qquad\longrightarrow \Bigg\lgroup Pressure =(Force)/(Area)\Bigg\rgroup\\\\

☯️
\underline{\underline{\boldsymbol{ On \ substituting \ the \ respective \ values \ }}}


\sf\qquad\longrightarrow Pressure =(Force)/(Area)\\\\


\sf\qquad\longrightarrow Pressure =(40,000\ N )/(125cm^2)\\\\


\sf\qquad\longrightarrow Pressure =( 40,000\ N * 10^4)/(125m^2)\\\\


\sf\qquad\longrightarrow \boxed{\pink{\frak{ Pressure = 3.2* 10^6 \ Pascal }}}


\rule{200}4

User Ivan Mishalkin
by
2.7k points