Question

8. Sulfur has a first ionization energy of 1000 kJ/mol. Photons of what frequency are required to ionize one mole of Sulfur?​

Answer 1

the frequency of photons
`v = 1.509*10^(39)Hz`

Step-by-step explanation:

Given: first ionization energy of 1000 kJ/mol.

No. of moles of sulfur = 1 mole

`\Delta E_1 = 1000KJ/mol`

We know that plank's constant

`h = 6.626*10^(-34) Js`

Let the frequency of photons be ν

Also we know that ΔE = hν

this implies ν = ΔE/h

`= (10^6J)/(6.626*10^(-34) Js)`

`v = 1.509*10^(39)Hz`

Hence, the frequency of photons
`v = 1.509*10^(39)Hz`