Question

CuSO4 + 2NaBr --> CuBr2 + Na2SO4 ? How many grams of CuSO4 are needed to react with 1.80 x 1024 molecules of NaBr?

Answer 1

`238.5gCuSO_4`

Step-by-step explanation:

Hello there!

In this case, by considering the given chemical reaction, it is possible for us to calculate the required grams of CuSO4 by considering its molar mass of 159.6 g/mol, the given molecules of NaBr, the Avogadro's number and the 1:2 mole ratio between these two in order to set up the following stoichiometric set up:

`1.80x10^(24)moleculesNaBr*(1molNaBr)/(6.022x10^(23)molecules NaBr)*(1molCuSO_4)/(2molNaBr) *(159.6gCuSO_4)/(1molCuSO_4)\\\\=238.5gCuSO_4`

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