Question

A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the

pressure of the gas.

Answer 1

`P \approx 225atm`

Step-by-step explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

`PV=nRT`

`P=(nRT)/(V)`

`P=(3.20*0.08206*300)/(350*10^(-3))`

`P=225.079atm`

`P \approx 225atm`