171k views
1 vote
A 3rd3^{\text{rd}}3rd3, start superscript, start text, r, d, end text, end superscript degree binomial with a constant term of 8888

Choose 1 answer:

Choose 1 answer:


(Choice A)

A

8x3+2x+38x^3+2x+38x3+2x+38, x, cubed, plus, 2, x, plus, 3

(Choice B)

B

2x8+32x^8+32x8+32, x, start superscript, 8, end superscript, plus, 3

(Choice C, Checked)

C

x3−x2+8x^3-x^2+8x3−x2+8x, cubed, minus, x, squared, plus, 8

(Choice D)

D

−5x3+8-5x^3+8−5x3+8minus, 5, x, cubed, plus, 8

1 Answer

1 vote

Answer:


-5x^3 + 8

Explanation:

See comment for complete question

Given


Degree \to 3rd


Constant \to 8


Type \to Binomial

Required

Which of the options is true


Type \to Binomial

This implies that the polynomial has just 2 terms

The above shows that (a), (b) and (c) are not true because they have more than 2 terms


Degree \to 3rd

This implies that the highest power of x is 3


Constant \to 8

The second term of the polynomial must be +8

Only (d) satisfy the above conditions

User Shun Min Chang
by
5.6k points