A body is thrown up with with velocity u.it reaches maximum height h. If velocity of projection is doubled the maximum height is..

Question

asked Jan 19, 2022 195k views

1 Answer

Dstricks · Answer 1 · 2022-01-23T03:37:19+0000

Answer: 4h

Step-by-step explanation:

Given

The body is thrown vertically upward with velocity u and reaches a height of h

The relation between u and h is given by

$\Rightarrow v^2-u^2=2as\\$

Put
v=0,a=-g in above equation

$\Rightarrow 0-u^2=2(-g)h\\\\\Rightarrow h=(u^2)/(2g)$

If the velocity of projection is doubled i.e. 2u

$\Rightarrow h'=((2u)^2)/(2g)\\\Rightarrow h'=4* (u^2)/(2g)\\\\\Rightarrow h'=4h$

The maximum height becomes 4h