Answer:
Indeed, the given triangle is a right triangle.
Explanation:
A triangle is formed by the following three points:
,
and
. Then, we construct the following vectors:
![\overrightarrow {BA} = (x_(2)-x_(1), y_(1)-y_(1))](https://img.qammunity.org/2022/formulas/mathematics/high-school/z7pct7zhmsleys0cc06jogvik1aocs6c1h.png)
(1)
![\overrightarrow{BC} = (x_(2)-x_(2), y_(2) - y_(1))](https://img.qammunity.org/2022/formulas/mathematics/high-school/nphpa4nrj8r01h190ouzifgrk4n3mebff7.png)
(2)
If triangle ABC is a right triangle, then
. By (1) and (2) we have this expression:
![(x_(2) - x_(1))\cdot (0) + (0)\cdot (y_(2) - y_(1)) = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/vvutoq4plnj8k84yd4ians3k4xmw0qofib.png)
Therefore, the given triangle is a right triangle.