Question

Adult male heights have a normal probability distribution with a mean of 70 inches and a standard deviation of 4 inches.

What is the probability that a randomly selected male is more than 66 inches tall?

Enter your answer in decimal form, e.g. 0.68, not 68 or 68%.

Answer 1

Answer: 0.84134

Explanation:

We need to find the z-score for the given information first since this will help us find the probability. The formula for this is

Z score =
`(x - \mu)/(\sigma)`

We have

`x =` 66 inches (the raw score)

`\mu =` 70 inches (the population mean)

`\sigma` = 4 inches (the standard deviation)

This gives

Z score =
`(x - \mu)/(\sigma)` =
`(66-70)/(4) = -1`

If you use a calculator, or a Z-score table then P(x > Z) is just P(Z > -1) which gives a probability of 0.84134.