Question

A pressure of 7x10^5N/m is applied to all surfaces of a copper cube (of sides 25 cm) what is the fractional change in volume of a cube? ( for copper B= 14x10^10N/m)

Answer 1

The correct solution is "
`5* 10^(-4)` %".

Step-by-step explanation:

The given values are:

Pressure,

`\Delta P=7* 10^5 \ N/m`

for copper,

`B=14* 10^(10) \ N/m`

As we know,

The Bulk Modulus (B) =
`(\Delta P)/(-(\Delta V)/(V) )`

or,

The decrease in volume will be:

=
`((\Delta V)/(V))* 100 \ percent`

then,

=
`(\Delta P)/(B)* 100 \ percent`

On putting the values, we get

=
`(7* 10^5)/(14* 10^(10))* 100 \ percent`

=
`5* 10^(-4) \ percent`