Question

The sides of a polygon are 3cm,5cm,6cm,8cm and 10cm.The perimeter of a similar polygons is 48cm.Find the sides of the second polygon.

Answer 1

`a'=4.5`

`b'=7.5`

`c'=9`

`d'=12`

`e'=15`

Explanation:

From the question we are told that:

Sides of Polygon 1

a=3

b=5

c=6

d=8

e=10

Perimeter of polygon 2 P_2=48

Generally the equation for Polygon 1 is mathematically given by

P_1=a+b+c+d+e

P_1=3+5+6+8+10

P_1=32

Generally the sides of similar polygon with Perimeter P_2=48 is mathematically given by

Side\ of\ polygon\ 2 =\frac{side\ of\ polygon\ 1}{perimeter\ of\ polygon\ 1}*perimeter\ of\ polygon\ 2

Therefore

`a'=(a)/(P_1)*P_2\\a'=(3)/(32)*48`

`a'=4.5`

`b'=(b)/(P_1)*P_2\\b'=(5)/(32)*48`

`b'=7.5`

`c'=(c)/(P_1)*P_2\\c'=(6)/(32)*48`

`c'=9`

`d'=(d)/(P_1)*P_2\\d'=(8)/(32)*48`

`d'=12`

`e'=(e)/(P_1)*P_2\\e'=(10)/(32)*48`

`e'=15`