Answer:
C. 0.025 < p < 0.05
Explanation:
The
goodness-of-fit test parameters are presented here as follows;
The number of Skittles in the bag = 30 Skittles
The different flavors in the bag of Skittles = Strawberry, orange, lemon, lime, and grape
The number of different flavors, n = 5 flavors
The
statistic = 10.20
Therefore, the degrees of freedom, d.f. = n - 1 = 5 - 1 = 4
Using the chi-square (
) distribution table, we have;
The probability at 4 degrees of freedom for a
statistic of 10.20 is between 0.025 and 0.05
Therefore, we get;
The probability (P > 10.20) = 0.025 < p < 0.05.