Question

71.1 mL of 0.695M rubidium hydroxide neutralized 89.7mL of sulfuric acid and solution of unknown concentration. Find the concentration of the acid

Answer 1

Answer: Concentration of the acid is 0.551 M.

Step-by-step explanation:

Given:
`V_(1)` = 71.1 mL,
`M_(1)` = 0.695 M

`V_(2)` = 89.7 mL,
`M_(2)` = ?

Formula used to calculate the concentration of acid is as follows.

`M_(1)V_(1) = M_(2)V_(2)`

Substitute the values into above formula as follows.

`M_(1)V_(1) = M_(2)V_(2)\\0.695 * 71.1 mL = M_(2) * 89.7 mL\\M_(2) = 0.551 M`

Thus, we can conclude that concentration of the acid is 0.551 M.