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Chris drops an egg with a parachute from the top of a building. The height, h, in feet, of the egg above the ground after t seconds is given

by h (t) = 100 - 16t2

After how many seconds does the egg hit the ground?

I

1 Answer

5 votes

Answer:

The egg hits the ground after 2.5 seconds.

Explanation:

Height of the egg:

The height of the egg after t seconds is given by:


h(t) = 100 - 16t^2

After how many seconds does the egg hit the ground?

This is t for which
h(t) = 0. So


h(t) = 100 - 16t^2


16t^2 - 100 = 0


16t^2 = 100


t^2 = (100)/(16)


t = \sqrt{(100)/(16)}


t = (10)/(4)


t = 2.5

The egg hits the ground after 2.5 seconds.

User Arun N A
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