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Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.
Prove △GEC ≅ △HFA.

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC. Prove △GEC ≅ △HFA.-example-1
User Sandeep Kakkar
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1 Answer

26 votes
26 votes


\\ \rm\hookrightarrow AE\cong FC

So parallelogram BGAE and HDFC are equal.

  • GE=FC

And

  • BG=HD

As BG=HD

  • GC=AH

Hence


\\ \rm\hookrightarrow \triangle GEC\cong \triangle HFA(SSA)

User Amudhan
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