Question

If 200 mL of a gas at 27 °C is cooled to -33 °C at a constant pressure, the volume will be

Answer 1

V2 = 159.48 mL

Step-by-step explanation:

Given the following data;

Initial volume = 200 mL

Initial temperature = 28°C

Final temperature = -33°C

To find the final volume, V2, we would use Charles law;

First of all, we would convert the temperature in Celsius to Kelvin.

Mathematically, it is given by the formula;

Kelvin = 273 + C

Substituting into the equation, we have;

Initial temperature, T1:

Kelvin = 273 + 28

Kelvin = 301K

Initial temperature, T1:

Kelvin = 273 - 33

Kelvin = 240K

To find new volume V2, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

`VT = K`

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Where;

V1 and V2 represents the initial and final volumes respectively.

T1 and T2 represents the initial and final temperatures respectively.

`(V1)/(T1) = (V2)/(T2)`

Making V2 as the subject formula, we have;

`V_(2)= (V1)/(T1) * T_(2)`

`V_(2)= (200)/(301) * 240`

`V_(2)= 0.6645 * 240`

V2 = 159.48 mL