Question

A sample of chlorine gas occupies a volume of 0.025L at 300 K. At 600K, what will the volume be?

A)808 L
B)50 L
C)0.050 L
D)0.088 L

Answer 1

Answer: The volume at 600 K will be 0.050 L.

Step-by-step explanation:

Given:
`V_(1)` = 0.025 L,
`T_(1)` = 300 K

`V_(2)` = ?,
`T_(2)` = 600 K

Formula used is as follows.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

Substitute the values into above formula as follows.

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))\\(0.025 L)/(300 K) = (V_(2))/(600 K)\\V_(2) = 0.050 L`

Thus, we can conclude that the volume at 600 K will be 0.050 L.