Question

What is the electric field strenght in units of N/C if the flux through a 2.0m by 1.0m rectangular surface is 396Nm2/C, if the electric field is uniform, and if the plane of the surface is at an angle of π/3 radians with respect to the direction of the field ?

Answer 1

The appropriate answer is "396 N/C".

Step-by-step explanation:

The give values are:

Rectangular surface,

`\Phi_e=396 \ N.m^2/C`

`a = 2 \ m`

`b = 1 \ m`

Angle,

`\theta =(\pi)/(3) \ radian`

Now,

The area of rectangle (A) will be:

=
`a* b`

=
`2* 1`

=
`2 \ m^2`

hence,

The electric field strength will be:

⇒
`\Phi_e=E.A Cos \theta`

or,

⇒
`E=(\Phi_e)/(ACos \theta)`

On putting the given values, we get

⇒
`=(396)/(2* Cos((\pi)/(3) ))`

⇒
`=(396)/(2* 0.5)`

⇒
`=(396)/(1)`

⇒
`=396 \ N/C`