Question

LO bisects &NLM, LM= 22, NO = 6, and LN= 14. What is the approximate value of x?

x= 3.8

x=9.4

x=51.3

x= 73.3

Answer 1

9.4

Explanation:

Given :

LM= 22, NO = 6, and LN= 14 ; MO = x

Since O bisects the triangle ;

LN / NO = LM / MO

14 / 6 = 22 / x

Cross multiply :

14 * x = 22 * 6

14x = 132

Divide both sides by 14

14x/14 = 132 / 14

x = 9.428

x = 9.4 ( 1 decimal place)