Question

2.3g of lithium chloride in 500cm3 of solution

Answer 1

0.109M

Step-by-step explanation:

Find molarity of the solution:

Molarity is defined as the ratio between the moles of the solute (Lithium Chloride in this case) per liter of solution. To solve this question we have to find the moles of LiCl and its volume as follows:

Moles LiCl -Molar mass: 42.394g/mol-

2.3g * (1mol / 42.394g) = 0.0543 moles

Volume in liters:

500cm³ * (1L / 1000cm³) = 0.500L

Molarity:

0.0543 moles / 0.500L =

0.109M