Question

Five lamp, each labbled "6V,3W" are operated at normal brightness. What is the total energy supplied to the lamps in five seconds.​

Answer 1

E = 75 J

Step-by-step explanation:

First, we will calculate the total power consumed by the five lamps:

`Total\ Power = P = (5)(Power\ of\ one\ lamp)\\P = (5)(3\ W)\\P = 15\ W`

Now, the energy supply can be calculated as follows:

`E = Pt`

where,

E = Energy = ?

t = time = 5 s

Therefore,

E = (15 W)(5 s)

E = 75 J