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Given that sin ø 21/29, what is the value of cos ø, for 0° < ø < 90%

User Timotheus
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1 Answer

4 votes

Answer:


(20)/(29)

Explanation:

Let x replace theta.

Apply pythagorean trig identity


\sin {}^(2) (x) + \cos {}^(2) (x) = 1


((21)/(29) ) {}^(2) + \cos {}^(2) (x) = 1


(441)/(841) + \cos {}^(2) (x) = 1


\cos {}^(2) (x) = 1 - (441)/(841)


\cos {}^(2) (x) = (400)/(841)


\cos(x) = (20)/(29)

Cosine is positve in 1st quadrant so the answer is


(20)/(29)

User Ddiez
by
3.7k points