Question

How do I solve this problem?

Answer 1

`10100`

Explanation:

Use this formula,

`(n)/(2) (2 {a} + d(n - 1)`

where n is the amount of even intergers, a is the starting term, d is the common difference.

• the amount of even intergers from 2 to 200 is 100
• The starting number is 2
• The common difference is 2

`(100)/(2) (4 + 2(99)`

`50(4 + 198)`

`50(202)`

`10100`