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Help meeee help plsssss

Help meeee help plsssss-example-1
User ErikR
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1 Answer

5 votes

Answer:

3a. 240 C

3b. 3666.67 A

Step-by-step explanation:

3a. Determination of the charge.

Current (I) = 2 A

Time (t) = 120 s

Charge (Q) =?

The charge, current and time are related by the following equation:

Charge (Q) = current (I) × time (t)

Q = It

With the above formula, we can obtain the charge as follow:

Current (I) = 2 A

Time (t) = 120 s

Charge (Q) =?

Q = It

Q = 2 × 120

Q = 240 C

Thus, the charge is 240 C

3b. Determination of the current

We'll begin by converting 220 KC to C. This can be obtained as follow:

1 KC = 1000 C

Therefore,

220 KC = 220 KC × 1000 C / 1 KC

220 KC = 220000 C

Next, we shall express 1 minute in second. This is shown below:

1 min = 60 s

Finally, we shall determine the current. This can be obtained as follow:

Charge (Q) = 220000 C

Time (t) = 60 s

Current (I) =?

Q = It

220000 = I × 60

Divide both side by 60

I = 220000 / 60

I = 3666.67 A

Thus, the current flowing through the bulb is 3666.67 A

User Giorgos
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4.9k points