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If you have 2.9 x 10^21 atoms of nitrogen, how many moles do you have?

User Mblakele
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1 Answer

3 votes

Answer: Approximately
0.48 * 10^(-2) \ \text{ mole}

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Step-by-step explanation:

There are roughly 6.02 * 10^23 atoms in one mole of any element. So we have 6.02 * 10^23 atoms in one mole of nitrogen.

We can then do the following conversion:


\left(2.9 * 10^(21) \ \text{ atoms of nitrogen} \right)* \left(\frac{1 \ \text{ mole}}{6.02 * 10^(23) \ \text{ atoms}}\right)\\\\(2.9 * 10^(21))/(6.02 * 10^(23)) \ \text{ mole}\\\\(2.9)/(6.02) * 10^(21-23) \ \text{ mole}\\\\0.48172757 * 10^(-2) \ \text{ mole}\\\\0.48 * 10^(-2) \ \text{ mole}\\\\

User Chernoff
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