Answer:
1.
For triangle 1
![a = 3√(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xsp4zcu96z4moktmad9rpyar1cqluywxmk.png)
For triangle 2
![x = 2√(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xassqll5bjhgbaqnvrpjee9hbj88j7iv61.png)
2.
Way 1
By reducing the length of the side 4 to 3.60
Way 2
By increasing the length of side 7 to 7.21
Explanation:
The complete question is attached in the image
Solution
1.
Both the triangles are right angled triangle
For triangle 1
![7^2 = 2^2 + a^2\\49 = 4 + a^2\\a^2 = 45\\a = 3√(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/m8hjuc9kgyefw5p5itti1g63i3ms953oah.png)
For triangle 2
![4^2 = x^2+x^2\\2x^2 = 4*4\\x^2 = 8\\x = 2√(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ieb4m8tfnbd4wc5eqbf08h2e0tuyu0lkav.png)
2.
Way 1
By reducing the length of the side 4 to 3.60
Way 2
By increasing the length of side 7 to 7.21