Question

A 1.25 m long pendulum on Mars

has a period of 3.65 s. What is the
acceleration of gravity g on Mars?
(Unit = m/s^2)
Help please

Answer 1

Step-by-step explanation:

`period = 2\pi \sqrt{ (length)/(g) }`

`3.65 \: s = 2\pi \sqrt{ ((1.25 \: m))/(g) }`

Squaring both sides and solving for g, we get

g = 3.70 m/s^2

which is close to what is expected (3.71 m/s^2).