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What is the pressure of a gas if the volume is 96.2 L, the temperature is 25⁰C and there are 1.24 moles?

User Xbrady
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1 Answer

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PV=nRT

P(96.2 L)= (1.24 mol)(8.314)(298 K)
P = 96.2/3072.18
P = 31.93 Pa or 0.031 kPa
User Joth
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