Question

Taco Quatro can make their entire menu out of their fantastic four Mexican ingredients, cheese, meat, beans and tortillas. A Nacholupa (N) needs 2 ounces of cheese, 4 ounces of beans and 3 tortillas. A Quesatilla (Q) needs 4 ounces of cheese, 2 ounces of meat and 1 tortilla. An Enchinacho (E) requires 2 ounces each of cheese, meat, and beans plus 3 tortillas. Their newest menu item, the Burritaco (B) needs 4 ounces of cheese, 2 ounces of meat and one tortilla. A Nacholupa sells for $2.75, a Quesatilla sells for $2, an Enchinacho sells for $3 and the new Burritaco sells for $4. The assistant manager checks the cooler one fine Monday morning and sees that they have 400 ounces of cheese, 150 ounces of meat, 400 ounces of beans and 250 tortillas on hand. Then how many units of each product should be produced to maximize the revenue

Answer 1

The solution is:

z (max ) = 446.25 $

x₁ = 55 x₂ = 0 x₃ = 5 x₄ = 70

Explanation:

From problem statement:

Nacholupa Quesatilla Enchinacho Burritaco

x₁ x₂ x₃ x₄

Cheese 2 4 2 4

meat 0 2 2 2

beans 4 0 2 0

Tortillas 3 1 3 1

Price $ 2.75 2 3 4

From table :

z = 2.75*x₁ + 2*x₂ + 3*x₃ + 4*x₄ to maximize

Subject to:

Availability of cheese: 400 ou

2*x₁ + 4*x₂ + 2*x₃ + 4*x₄ ≤ 400

Availability of meat : 150 ou

2*x₂ + 2*x₃ + 2*x₄ ≤ 150

Availability of beans : 400 ou

4*x₁ + 2*x₃ ≤ 400

Availability of tortillas : 250

3*x₁ + x₂ + 3*x₃ + x₄ ≤ 250

General constraints:

x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 x₄ ≥ 0

All integers

With the use of AtomZmath ( integer solving on-line software )

The solution is:

z (max ) = 446.25 $

x₁ = 55 x₂ = 0 x₃ = 5 x₄ = 70