Question

Calculate the concentration of NO2NO2 in an equilibrium mixture given that the concentration of N2O4=0.200MN2O4=0.200M and Keq=67.3Keq=67.3 for the reaction: 2NO2(g)⇌N2O4(g)2NO2(g)⇌N2O4(g). Calculate the concentration of in an equilibrium mixture given that the concentration of and for the reaction: . 18.3 M 0.00297 M 337 M 0.0545 M none of the above

Answer 1

Answer: The concentration of
`NO_(2)` in the given equilibrium mixture is 0.0545 M.

Step-by-step explanation:

The ratio of concentration of products and reactants raised to the power of their coefficients is called equilibrium constant. The symbol used to denote equilibrium constant is
`K_(eq)`.

As the given reaction equation is as follows.

`2NO_(2)(g) \rightleftharpoons N_(2)O_(4)(g)`

The expression for equilibrium constant of this reaction is as follows.

`K_(eq) = ([N_(2)O_(4)])/([NO_(2)]^(2))`

Now, substitute the given values into above formula as follows.

`K_(eq) = ([N_(2)O_(4)])/([NO_(2)]^(2))\\67.3 = ((0.2))/([NO_(2)]^(2))\\So, [NO] = \sqrt{(0.2)/(67.3)}\\= 0.0545 M`

Thus, we can conclude that the concentration of
`NO_(2)` in the given equilibrium mixture is 0.0545 M.