Question

A spring is hung from the ceiling. When a coffee mug is attached to its end, it stretches 2.5 cm before reaching its new equilibrium length. The block is then pulled down slightly and released. What is the frequency of oscillation

Answer 1

Step-by-step explanation:

In equilibrium , weight of mug is equal to restoring force .

mg = kx where m is mass of mug , k is spring constant and x is extension .

k / m = g / x = 9.8 ms⁻² / .025 m

= 392

frequency of oscillation n =
`(1)/(2\pi)\sqrt{(k)/(m) }`

`n=(1)/(2\pi)√(392 )`

= 4.46 per second.