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You have have a bag of marbles (3 purple, 5 green, and 4

yellow)
Write your probability in fraction form-no need to reduce
1a) What is the Plyellow marble)=
1b) What is the P(purple marble)=
1c) What is the Plyellow marble "and" purple marble)
1a) 4/12, 1b) 3/12, 1c) 12/12
1a) 4/100, 1b) 3/100, 1c) 12/100
1a) 4/12, 1b) 3/12, 1c) 12/144
1a) 4, 1b) 3, 1c) 12

User Coorasse
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2 Answers

1 vote

Answer:

The answer to this is the 3rd choice which is 1a) 4/12, 1b) 3/12, 1c) 12/144.

Explanation:

This is pretty simple. To identify the probability of the yellow marbles, you can find the amount of yellow marbles and the total amount of marbles. You take it as a fraction which would be 4/12.

The total amount of marbles : 3 purple + 5 green + 4 yellow = 12 total marbles

The amount of yellow marbles : 4 yellow

Probability of yellow marbles : 4/12

To identify the probability of the yellow marbles, you can find the amount of purple marbles and the total amount of marbles. You take it as a fraction which would be 3/12.

The total amount of marbles : 3 purple + 5 green + 4 yellow = 12 total marbles

The amount of purple marbles : 3 purple

Probability of purple marbles : 3/12

To identify the probability of both the yellow and purple marbles, you can find the amount of yellow and purple marbles along with the total amount of marbles. Since we know this from the work above, you just need to multiply both probabilities. You take it as a fraction which would be 12/144.

The total amount of marbles : 3 purple + 5 green + 4 yellow = 12 total marbles

The amount of yellow marbles : 4 yellow

The amount of purple marbles : 3 purple

Probability of yellow marbles : 4/12

Probability of purple marbles : 3/12

Probability of both marbles : 12/144

User Boban Stojanovski
by
4.9k points
4 votes

Answer:

4/12 = yellow

3/12 = purple

12/144 = yellow and purple

Explanation:

the first two are pretty self explanitory. The last one requires you to multiply the answers of the first two together. Make sure you multiply both the top and the bottom (don't use common denominator here)

User Kcsquared
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5.1k points