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Sheldon spins the two spinners below one time what are the chance he will spin 3 or c ?

User Kingchris
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1 Answer

6 votes

Answer:


P(3\ or\ c) = 0.45

Explanation:

Given

See attachment for spinner

Required


P(3\ or\ c)

From the first spinner, we have:


S = \{1,2,3,4,5\} --- Sample Space


n(S)=5

So, P(3) is:


P(3) = (n(3))/(n(S))


P(3) = (1)/(5)


P(3) = 0.20

From the second spinner, we have:


S = \{a,b,c,d\}


n(S) = 4

So, P(c) is:


P(c) = (n(c))/(n(S))


P(c) = (1)/(4)


P(c) = 0.25

The required probability is then calculated as:


P(3\ or\ c) = P(3) + P(c)


P(3\ or\ c) = 0.20 + 0.25


P(3\ or\ c) = 0.45

Sheldon spins the two spinners below one time what are the chance he will spin 3 or-example-1
User Shaun Wild
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