9514 1404 393
Answer:
b. 10.2 yards
Explanation:
The quadratic formula tells you the solutions to ...
ax² +bx +c = 0
are given by ...
![x=(-b\pm√(b^2-4ac))/(2a)](https://img.qammunity.org/2022/formulas/mathematics/college/9swrgeptcnpvia934oshvwyq1osnvcksac.png)
Here, the quadratic equation we have is ...
h² +5h -155 = 0
So the solutions given by the quadratic formula are ...
![h=(-5\pm√(5^2-4(1)(-155)))/(2(1))=(-5\pm√(645))/(2)=\{-15.2,10.2\}](https://img.qammunity.org/2022/formulas/mathematics/college/ic6hc10jta1j2tezaympdb95cg9ztaxt9x.png)
The negative solution is not applicable in this situation, so the height that gives the desired area is 10.2 yards.