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Write the equation of a line with a slope of 2/3 going through the point (-15, -22)

1 Answer

4 votes

Answer:

y=(2/3)(x+15)-22

Explanation:

You use the slope point equation which is y-y1=m(x-x1) or y=m(x-x1)+y1 where m is the slope and x1 and y1 are the coordinates you plug in.

Therefore, 2/3 is the slope m and (-15, -22) are the coordinates for x1 and y1.

y=(2/3)(x-(-15)) + (-22)

y=(2/3)(x+15)-22

User Roblanf
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